WR Home Topic Home | Chapter: 1 2 |
<Previous | Next> |
Chapter 02
Basics of Animation and Forward Kinematics
Page 5
What will be the values of lx and ly if the arm is "sleeping" on horizontally, in the first quadrant ?
.
.
.
.
.
.
.
HINT:
The soloution is given below:
Consider the following arm position:
L1 = 110.0; % Link Length in mm L2 = 140.0; % Link Length in mm lx(1) = 0.0; ly(1) = 0.0; lx(2) = lx(1) + L1; ly(2) = ly(1); lx(3) = lx(2) + L2; ly(3) = ly(2);So, this was simple.
WR Home Topic Home | Chapter: 1 2 |
<Previous | Next> |